Page 159 - Special Topic Session (STS) - Volume 2
P. 159

STS474 Yoshihiro Y.
            (3)  For   =    (which  we  assume  as  an  integer),  the  kernel   =
                          ⁄
                                                                                    
                 ∑   ℎ exp() satisfies
                  =1
                      
                                               () sin ( 2)
                                                           ⁄
                                                
                                                               
                                       (λ) =   −1  [  sin(  2)  ] ,
                                       
                                                           ⁄
            where  () is a complex function, whose modulus is bounded and bounded
                    
            away from zero, with  − 1 derivatives, all bounded in modulus as 
            increases for  ∈ [−, ].
                Then we define the discrete Fourier transform (DFT)  ( ,  ) and the
                                                                    
                                                                            2
                                                                        1
            periodogram  ( ,  ) by
                          
                               1
                                   2
                     ( ,  )  =     1       
                     
                          1
                              2
                                                                            )),
                                                ∑ ℎ ℎ ( ) exp((
                                     2 ∑   ℎ  2  ,=1         1 , 2 , 
                                         =1
                                                  2
                     ( ,  )  =  | ( ,  )| ,
                                       
                     
                                            1
                             2
                                               2
                         1
            respectively where   1 2  is the bivariate Fourier frequency,
                                         2 1  2 2  ( − 1)       
                        = ( ,  ) = (     ,     ) , [  2   ], ≤  ,  ≤ [ ],
                                                                   1
                                                                     2
                         
                                    2
                                1
                                                                          2
            and [] is the integer part of  and {ℎ } is a sequence of data tapers of order
                                                 
            .
                Next we define the normalized DFT by
                                   (  1 , 2 )  =     (  1  ,  2 )  ,
                                  
                                                  2
                                                      2
                                              (( + ) −(+1) ) 1/2
                                                       2
                                                   1
                                 (  1 , 2 )  = Re( ((  1 , 2 )),
                                 
                                                  
                                 (  1 , 2 )  = Im( ((  1 , 2 )),
                                 
                                                  
            where   =  , (0,0)/(8 ). H
                                     2
                         0
                Now  we  introduce  the  estimator.  We  denote  by    and   the  true
                                                                     0
                                                                             0
            parameters, and by  and  any admissible values. Then define the closed
            interval  of  admissible  parameters  of  , ℋ = [∆ , ∆ ],  where ∆ and ∆ are
                                                                2
                                                             1
                                                                                   2
                                                   0
                                                                            1
            numbers  chosen  such  that  0  <  ∆  < ∆  <  1.  We  can  choose  ∆  and ∆
                                                                              1
                                                     2
                                               1
                                                                                      2
            arbitrarily close to 0 and 1 respectively. Next consider the objective function
                         (, )  =   1  ∑ {log (( 2  +  2  ) −−1 )
                                                        1    2 
                                         ( 1,  2)∈ 
                                            2
                                                   2
                                         (  1   +   2  ) +1
                                       +                    (  1 , 2  )},
                                                            
                                                 
            where
                    =   {(  ) | ,  ≤ (  1  ) + (  2  ) ≤  , , 0 <  ,  ,  ≤   2  ≤  },
                                                    2
                                           2
                                 2
                                                         2
                  
                                                                       
                                                                                
                                                                 1
                                                                    2
                           1, 2
                                        
                                                 
                          < 1 <  ,                                      1
                          
                                   
            and  is the cardinality of   .   plays an important role so that   (  1 , 2  )
                                                                           
                                       
            and    (  1 , 2  ) are  asymptotically  independent  if (  ) ≠ (  ).  Then
                                                                            1, 2
                                                                   1, 2
                  
            the estimator exists.
                                   ̂ ̂
                                    ,  = arg  min    (, ),
                                       
                                    
                                               0<<∞,ℋ
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