Page 95 - Contributed Paper Session (CPS) - Volume 2
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CPS1442 Uzuke C.A. et al.
            would conform to a mixed effect model with one observation per cell that is
            without replications, Esinga et al, (2017). Here this assumption is not necessary.
                As in the Friedmans two-way ANOVA by ranks, the data being analysed
            may  be  presented  in  the  form  of  a  two-way  r   table  with  the  row  say
                                                              c
            representing one factor A with r levels say and the columns say representing
            the other factor B with c levels Daniels, (1990). Factors A and B may both be
            fixed, both random, or one of the factor fixed and the other random. Here two
            null hypotheses are to be tested. One is that there are no differences between
            the c treatment effects for the column factor B and the second is that there
            are no differences between the effects of the r levels of the row factor A.
                To develop the test statistics for the column factor B based on the median
            test we first pull all the observation in the table together and determine the
            common median M as usual Oyeka & Uzuke, (2011).. Now if the jth level of
            factor B has median  M for j = I, 2, …, c then the null hypothesis to be tested
                                   j
            for factor B is

            Ho: M1 = M2 = … = Mj … = Mc = M
                                         (1)
                Now let  x be the score on observation on a randomly selected subject at
                          ij
            the ith level of factor A and jth level of factor B on a certain numeric criterion
            variable X, measured in at least the ordinal scale for I = 1, 2 , …, r; j = 1, 2, …, c
            Let
                   , 1  if    x   M
                               ij
            U ij  = 0 ,  if    x ij  = M                                            (2)
                  
                  
                   − , 1  if    x ij   M
            For i=1, 2, …, r; j = 1, 2, …, c
            Let
             +               0                   −
                    U
              j  = P ( );    j  = P ( U ij  =  ); 0   j  = P ( U ij  =  −  ) 1          (3)
                      ij
            Where
             +    0    −
              j +   j +   j  = 1                                                 (4)
            And
                   r
            U  j  =  U                                                             (5)
                      ij
                   = i 1
            Finally, let
                          c
                             r
                  c
            W  =   U  j  =  U                                                    (6)
                                 ij
                  = j 1   = j 1  = i 1


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