Page 163 - Contributed Paper Session (CPS) - Volume 7
P. 163

CPS2051 Mentje G. et al.
                   As illustration of the complexity of the experts’ task, take  = 50 then    =
                                                                                      7
                −1 (0.99714) ,  20  =  −1 (0.999) and  100  =  −1 (0.9998)  which implies that the
               quantiles that have to be estimated are very extreme.

               2.3 Estimating VaR
                   In the previous section we discussed a way of modelling the true severity
               distribution  .  The  estimation  of  the  99.9%  VaR  of  the  aggregate  loss
               distribution is of interest and de Jongh et al. (2015) discuss three approaches
               to estimate it, namely the naïve approach, the generalized Pareto distribution
               (GPD)  approach  and  Venter’s  approach.  The  naïve  approach  make  use  of
               historical data only, whereas the GPD approach (which is based on a mixed
               model formulation) and Venter’s approach make use of both historical data
               and scenario assessments. Below we focus our discussion on the GPD and
               Venter approaches and in Section 3 we demonstrate that, as far as estimating
               VaR is concerned, that Venter’s approach is preferred.
               2.4 The GPD approach
                   Select a number  and let   be the corresponding quantile given by (1),
                                              
                                 1
               i.e.,   =  −1  (1 −  ). We use   as a threshold that splice  in such a way that
                    
                                             
                                 
               the  interval  below   is  the  expected  part  and  the  interval  above   the
                                    
                                                                                     
               unexpected part of the severity distribution. Define two distribution functions
                                       () = ()/( ) for  ≤   and
                                                       
                                                                 
                                       
                                 () = [() − ( )]/[1 − ( )]  for  >  ,
                                                                           
                                                               
                                                   
                                 
               i.e.  () is the conditional distribution function of a random loss ~ given
               that   ≤   and  () is the conditional distribution function given that   >
                          
                                 
                 . Note that we then have the identity
                 
                           () = T(  ) () + [1 − ( )] () for all .   (2)
                                                            
                                         
                                      
                                                        
                   This  identity  represents  ()  as  a  mixture  of  the  two  conditional
               distributions. Instead of modelling () with a class of distributions (, ) we
               may  now  consider  modelling   ()  with   (, ) and   () ,  with   (, ) .
                                                                      
                                                          
                                               
                                                                                   
               Borrowing from extreme value theory, a popular choice for  (, θ) could be
                                                                           
               the GPD, while a host of choices are available for  (, θ), the obvious being
                                                                 
               the empirical distribution.
                   Suppose we have available  years of historical loss data  ,  … ,    and
                                                                                    
                                                                           1
                                                                              2,
               scenario assessments ̃ , ̃  and ̃ 100 . Then the annual frequency   can  be
                                      7
                                         20
                             ̂
               estimated as  =   ⁄ . Next  and the threshold   must be specified. One
                                                                  
               possibility is to take  as the smallest of the scenario -year multiples and to
               estimate   as  the  corresponding  smallest  of  the  scenario  assessments ̃
                         
                                                                                         
               provided by the scenario makers, in this case ̃ .  () can be estimated by
                                                              7
                                                                 
               fitting a parametric family  (, θ) (such as the Burr) to the data  ,  , … , 
                                                                                1
                                                                                   2
                                                                                         
                                          
               or by calculating the empirical distribution and then conditioning it to the
                                                  ̃
               interval  (0, ̃ ].  We  denote  it  by  ().  For  the  sake  of  future  notational
                            
                                                  
                                                                  150 | I S I   W S C   2 0 1 9
   158   159   160   161   162   163   164   165   166   167   168