Page 101 - Contributed Paper Session (CPS) - Volume 2

CPS1442 Uzuke C.A. et al.
with 2(c – 1) degrees of freedom,  2 . 0 95 4 ; = 9.488 with a p-value of 0.093054

the null hypothesis of equal median reduction of heart beat among the
different dose levels of drug is not rejected.
Furthermore, the null hypothesis of equal median reduction in heart beat of
male patients under study was equally tested by obtaining the test statistic
using Equation 18 as:
c  r  2  r  2  r  

+
2
 =  p 1 − p −  p + + ) +  p 1 − p +  p − − ) +  2 + p −  ( − p + )( − p − )  
−
+
−
( ) ( − p
p
( ) ( − p
 p
p


−
( − p
p + p 1 + − − ) p  = i 1 i   = i i   = i 1 i i  
Using data of Table 2 we have that the test statistic is:
3
 2 = ( ( . 0 529344 + . 0 ) ( 6531872 ))
) ( 421054 −
. 0
. 0
. 0
. 0
( 47 )( 40 )( 13 )
2
 = 36.4825.
with 2(r – 1) degrees of freedom,  2 . 0 95 ; 28 = 42.557 with a p-value of 0.13073,
the null hypothesis of equal median reduction of heart beat among the male
patients under study is not rejected.
Also the friedman Two – way Analysis of variance by ranks used to test the
hypothesis of equal treatment effect was used to compare the result obtained.
The test statistic is as follows
12 c
 2 =  R 2 − r ( + ) 1
3 c
rc ( + ) 1 = j 1 j
c
For equal reduction of heart beat among the dose level of the drug, the test
statistic is
 2 = . 0 433 with a p-value of 0.805333.
For equal reduction of heart beat among male patients, the test statistic is
 2 = 18 8 . with a p-value of 0.172330
The results were summarized in table 3
Table 3 Summary of the result
TEST Factors  2 Test Degrees  Critical p-value
2
Statistic of Value
Freedom
Friedmann Dose level 0.433 2 5.991 0.805333
Patients 18.8 14 23.685 0.172330
Two Way Dose level 7.69 4 9.488 0.093054
Median Test Patients 36.48 28 42.557 0.130730

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